{"id":3224,"date":"2026-10-18T06:18:55","date_gmt":"2026-10-18T03:18:55","guid":{"rendered":"https:\/\/mits.sa\/%d8%ad%d8%b3%d8%a7%d8%a8-%d9%88%d8%b2%d9%86-%d8%a7%d9%84%d8%b5%d8%a7%d8%ac-%d9%88%d8%a7%d9%84%d9%85%d9%88%d8%a7%d8%b3%d9%8a%d8%b1\/"},"modified":"2026-10-18T06:18:55","modified_gmt":"2026-10-18T03:18:55","slug":"steel-sheet-pipe-weight-formula","status":"publish","type":"post","link":"https:\/\/mits.sa\/en\/steel-sheet-pipe-weight-formula\/","title":{"rendered":"How to calculate the weight of sheet metal, pipes, and sections? Equations with examples"},"content":{"rendered":"<p>The weight of any piece of iron = its volume \u00d7 the density of iron, and the density of carbon steel is approximately 7850 kg\/m\u00b3. From this rule, we can derive quick equations: the weight of sheet metal in kilograms = length (m) \u00d7 width (m) \u00d7 thickness (mm) \u00d7 7.85, the weight of a round pipe per meter = (outer diameter \u2212 thickness) \u00d7 thickness \u00d7 0.02466, and the weight of reinforcing steel per meter = diameter\u00b2 \u00f7 162.<\/p>\n<div class=\"mits-box\"><strong>In short:<\/strong><\/p>\n<ul>\n<li>All equations are derived from: Weight = Cross-sectional area \u00d7 Length \u00d7 7850 kg\/m\u00b3.<\/li>\n<li>Sheet metal: m \u00d7 m \u00d7 mm \u00d7 7.85 = kg.<\/li>\n<li>Round and square pipe: Calculate the area of the metal in the cross-section and then multiply it by 0.00785 to get kg\/m\u00b2.<\/li>\n<li>Reinforcement: Diameter in millimeters squared \u00f7 162 = kg per linear meter.<\/li>\n<li>The weights are calculated theoretically, and the actual weight varies slightly due to variations in thickness, bending angles, and galvanizing.<\/li>\n<\/ul>\n<\/div>\n<h2>What is the basic rule for calculating the weight of iron?<\/h2>\n<p>Iron is a nearly homogeneous material, so the weight of any piece is determined solely by its volume. If you know the volume of the piece in cubic meters, multiply it by 7850 to get the weight in kilograms. However, volume in cubic meters is a small and cumbersome number for everyday calculations, so engineers and technicians convert the equation to practical units: lengths in meters and thicknesses in millimeters.<\/p>\n<p>The concise rule from which all equations are derived: <strong>One linear meter of metal with a cross-sectional area of 1 mm\u00b2 weighs 0.00785 kg<\/strong>. That is, you calculate the area of the metal in the cross-section in square millimeters, then multiply it by 0.00785 to get the weight in kilograms per meter, then multiply by the length.<\/p>\n<p>This method is suitable for any sector: sheet metal, pipes, angles, flats, beams, and even custom-shaped pieces.<\/p>\n<div class=\"mits-box mits-calc\"><strong>Calculate it yourself:<\/strong> Choose the type of piece (sheet metal, pipe, section, or reinforcement) and enter the dimensions, and the calculator will give you the weight per meter and for the entire quantity without manual calculation. <a href=\"\/en\/steel-weight-calculator\/\">Open the free calculator<\/a><\/div>\n<h2>How do you calculate the weight of a sheet of iron?<\/h2>\n<p>The sheet metal is rectangular with a constant thickness, so the equation is straightforward:<\/p>\n<p><strong>Weight (kg) = Length (m) \u00d7 Width (m) \u00d7 Thickness (mm) \u00d7 7.85<\/strong><\/p>\n<p>The figure 7.85 represents the weight of one square meter of sheet metal with a thickness of 1 mm. This means that for every square meter of thickness, the weight increases by 7.85 kg.<\/p>\n<h3>Illustrative example: sheet metal<\/h3>\n<ul>\n<li>A 1.25 x 2.5 meter slab with a thickness of 2 mm: 1.25 x 2.5 x 2 x 7.85 \u2248 49.1 kg.<\/li>\n<li>A 1 x 2 meter board with a thickness of 1.5 mm: 1 x 2 x 1.5 x 7.85 \u2248 23.6 kg.<\/li>\n<li>Base (plate) 200 \u00d7 200 mm with a thickness of 10 mm: 0.2 \u00d7 0.2 \u00d7 10 \u00d7 7.85 \u2248 3.1 kg.<\/li>\n<\/ul>\n<p>For sheet metal components, such as cable trays or bent sections, calculate the sheet width before bending (the sum of the lengths of the straight sides) and then apply the same equation. This makes thickness a crucial factor in the weight of the cable tray, as explained in the article. <a href=\"\/en\/cable-tray-sizing\/\">Choosing the cable tray size, fill percentage, and weights<\/a>.<\/p>\n<h2>How do you calculate the weight of a circular pipe?<\/h2>\n<p>The area of metal in a pipe cross-section is the difference between two circles, and after simplification the equation becomes:<\/p>\n<p><strong>Weight (kg\/m) = (Outer Diameter \u2212 Thickness) \u00d7 Thickness \u00d7 0.02466<\/strong><\/p>\n<p>Where the diameter and thickness are in millimeters. The number 0.02466 is the product of \u03c0 (3.1416) \u00d7 0.00785.<\/p>\n<h3>Illustrative example: pipes<\/h3>\n<ul>\n<li>A pipe with an outer diameter of 114.3 mm and a thickness of 4 mm: (114.3 \u2212 4) \u00d7 4 \u00d7 0.02466 \u2248 10.9 kg\/m, and a length of 6 meters weighing approximately 65.3 kg.<\/li>\n<li>60.3 mm pipe with a thickness of 3 mm: (60.3 \u2212 3) \u00d7 3 \u00d7 0.02466 \u2248 4.24 kg\/m.<\/li>\n<\/ul>\n<p>Note that pipes are sometimes labeled in inches (2 inches, 4 inches), but this is a nominal size and does not represent the actual outer diameter. Always use the actual outer diameter in millimeters from the supplier&#039;s chart.<\/p>\n<h2>How do you calculate the weight of square, rectangular, and angle pipes?<\/h2>\n<p>For a square pipe with an outer side a and a thickness t, the area of the metal is approximately 4 \u00d7 t \u00d7 (a \u2212 t), so the equation is:<\/p>\n<p><strong>Squared (kg\/m\u00b2) = 4 \u00d7 t \u00d7 (a \u2212 t) \u00d7 0.00785<\/strong><\/p>\n<p><strong>Rectangular a \u00d7 b (kg\/m) = 2 \u00d7 t \u00d7 (a + b \u2212 2t) \u00d7 0.00785<\/strong><\/p>\n<p><strong>Equilateral angle (kg\/m) \u2248 (2a \u2212 t) \u00d7 t \u00d7 0.00785<\/strong><\/p>\n<p><strong>Simplified (flat) with width w (kg\/m) = w \u00d7 t \u00d7 0.00785<\/strong><\/p>\n<p><strong>Solid round iron with a diameter of d (kg\/m) = d\u00b2 \u00d7 0.00617<\/strong><\/p>\n<h3>Illustrative example: Sectors<\/h3>\n<ul>\n<li>Square 50 \u00d7 50 \u00d7 2 mm: 4 \u00d7 2 \u00d7 48 \u00d7 0.00785 \u2248 3.01 kg\/m, and a length of 6 meters is approximately 18.1 kg.<\/li>\n<li>Square 100 \u00d7 100 \u00d7 4 mm: 4 \u00d7 4 \u00d7 96 \u00d7 0.00785 \u2248 12.1 kg\/m.<\/li>\n<li>Rectangular 100 \u00d7 50 \u00d7 3 mm: 2 \u00d7 3 \u00d7 (150 \u2212 6) \u00d7 0.00785 \u2248 6.78 kg\/m.<\/li>\n<li>Angle 50 \u00d7 50 \u00d7 5 mm: (100 \u2212 5) \u00d7 5 \u00d7 0.00785 \u2248 3.73 kg\/m.<\/li>\n<li>Simplified 50 \u00d7 5 mm: 50 \u00d7 5 \u00d7 0.00785 \u2248 1.96 kg\/m.<\/li>\n<\/ul>\n<p>These equations ignore the roundness of the corners in square pipes, so the actual weight in the manufacturers\u2019 tables is slightly less than the output, a small difference that is sufficient for estimation in calculating the initial quantities.<\/p>\n<h2>How do you calculate the weight of reinforcing steel using the equation diameter\u00b2 \u00f7 162?<\/h2>\n<p>The reinforcing bar has an almost solid circular cross-section, so its weight per meter = d\u00b2 \u00d7 0.00617. Since 1 \u00f7 162 \u2248 0.00617, the common equation on websites is:<\/p>\n<p><strong>Weight per meter (kg) = Diameter (mm)\u00b2 \u00f7 162<\/strong><\/p>\n<table class=\"mits-t\">\n<thead>\n<tr>\n<th>The diameter of the rebar (mm)<\/th>\n<th>Approximate weight (kg\/m)<\/th>\n<th>Weight of a 12-meter rebar (kg)<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>8<\/td>\n<td>0.395<\/td>\n<td>4.74<\/td>\n<\/tr>\n<tr>\n<td>10<\/td>\n<td>0.617<\/td>\n<td>7.41<\/td>\n<\/tr>\n<tr>\n<td>12<\/td>\n<td>0.889<\/td>\n<td>10.67<\/td>\n<\/tr>\n<tr>\n<td>16<\/td>\n<td>1.580<\/td>\n<td>18.96<\/td>\n<\/tr>\n<tr>\n<td>20<\/td>\n<td>2.469<\/td>\n<td>29.63<\/td>\n<\/tr>\n<tr>\n<td>25<\/td>\n<td>3.858<\/td>\n<td>46.30<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>To calculate the tonnage of reinforcement for a concrete element: add up the lengths for each diameter, multiply by the weight per meter, then add a percentage for overlaps (connections) and waste according to the details of the plans.<\/p>\n<h2>Summary of equations and tips for calculating quantities<\/h2>\n<table class=\"mits-t\">\n<thead>\n<tr>\n<th>piece<\/th>\n<th>The equation<\/th>\n<th>Units<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>Saj<\/td>\n<td>Length \u00d7 Width \u00d7 Thickness \u00d7 7.85<\/td>\n<td>m, m, mm \u2190 kg<\/td>\n<\/tr>\n<tr>\n<td>circular pipe<\/td>\n<td>(Diameter \u2212 Thickness) \u00d7 Thickness \u00d7 0.02466<\/td>\n<td>mm \u2190 kg\/m<\/td>\n<\/tr>\n<tr>\n<td>square pipe<\/td>\n<td>4 \u00d7 t \u00d7 (a \u2212 t) \u00d7 0.00785<\/td>\n<td>mm \u2190 kg\/m<\/td>\n<\/tr>\n<tr>\n<td>rectangular pipe<\/td>\n<td>2 \u00d7 t \u00d7 (a + b \u2212 2t) \u00d7 0.00785<\/td>\n<td>mm \u2190 kg\/m<\/td>\n<\/tr>\n<tr>\n<td>Reinforcing steel<\/td>\n<td>Diameter\u00b2 \u00f7 162<\/td>\n<td>mm \u2190 kg\/m<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h3>Illustrative example: a small metal frame<\/h3>\n<p>A frame made of 8 square tubes (50 x 50 x 2 mm, each piece 3 meters long) with 4 sheet metal bases (200 x 200 x 10 mm). Figures are approximate.<\/p>\n<ol>\n<li>Pipes: 8 x 3 = 24 meters x 3.01 \u2248 72.2 kg.<\/li>\n<li>Bases: 4 x 3.1 \u2248 12.6 kg.<\/li>\n<li>The theoretical total is about 85 kg, plus the weight of the bolts, welding, and zinc coating if the frame is galvanized.<\/li>\n<\/ol>\n<p>Practical tips:<\/p>\n<ul>\n<li><strong>Galvanizing adds weight:<\/strong> The zinc coating in hot-dip galvanizing adds a small percentage of weight, depending on the thickness and surface area of the workpiece. The differences between galvanizing methods are explained in the article. <a href=\"\/en\/cable-tray-hot-dip-vs-pre-galvanized\/\">Hot-dip galvanizing or electro-galvanizing<\/a>.<\/li>\n<li><strong>Aluminum is about two-thirds lighter:<\/strong> Its density is about 2700 kg\/m\u00b3, which is about 0.34 times the weight of iron of the same dimensions.<\/li>\n<li><strong>Stainless steel is slightly heavier:<\/strong> Its density is in the range of 7900 to 8000 kg\/m\u00b3 depending on the grade.<\/li>\n<li><strong>Calculate the loss separately:<\/strong> The weight of the finished pieces does not equal the weight of the raw material purchased, as cutting slabs and lengths leaves residues.<\/li>\n<\/ul>\n<h2>Why is it important to calculate the weight before manufacturing?<\/h2>\n<p>Weight is not a number to be trifled with. It is the basis for several decisions in any mining project:<\/p>\n<ul>\n<li><strong>Cost estimation:<\/strong> Iron is often priced by weight, so knowing the weight gives you a preliminary picture of the cost of materials before requesting bids.<\/li>\n<li><strong>Structural loads:<\/strong> Solar panel structures on roofs, for example, add a load that the roof must bear, and the weight of the structure is part of this calculation.<\/li>\n<li><strong>Transportation and lifting:<\/strong> The number of trucks and the type of crane depend on the total weight and the longest piece.<\/li>\n<li><strong>Comparing the offers:<\/strong> Two offers with the same dimensions but very different weights often mean different thicknesses, so ask about the thickness before comparing.<\/li>\n<\/ul>\n<p>And in <a href=\"\/en\/factory\/\">MITS Metal Manufacturing Plant<\/a> In Al-Kharj, the weights of the pieces are calculated from the plans before cutting and shaping, whether they are cable trays, panel structures, or <a href=\"\/en\/factory-products\/custom-cnc-metal-parts\/\">Custom-made metal parts with CNC machining<\/a>This helps the customer know the quantity and weight before implementation.<\/p>\n<h2>Frequently Asked Questions<\/h2>\n<div class=\"mits-faq\">\n<h3>Why does the calculated weight differ from the weight on the scale?<\/h3>\n<p>Because the actual thickness varies within manufacturing tolerances, the angles in the pipes are rounded, and galvanizing adds a zinc layer. The difference is usually small but noticeable in large quantities.<\/p>\n<h3>What is the weight of one square meter of 1 mm sheet metal?<\/h3>\n<p>Approximately 7.85 kg. Therefore, one square meter with a thickness of 2 mm weighs approximately 15.7 kg, and with a thickness of 3 mm weighs approximately 23.6 kg.<\/p>\n<h3>Is the equation diameter\u00b2 \u00f7 162 minutes?<\/h3>\n<p>This is an excellent approximation of the theoretical weight of a solid rebar with a density of 7850. Ribbed rebars may vary slightly depending on the specification, so refer to the manufacturer&#039;s table for final calculations.<\/p>\n<h3>How do I calculate the weight of a complex object?<\/h3>\n<p>Divide it into simple parts (sheets, pipes, and bases), calculate each part separately, then add them up. Subtract the weights of any large openings.<\/p>\n<\/div>\n<div class=\"mits-cta\">\n<p><strong>Do you need to manufacture metal parts or structures according to your plans?<\/strong> MITS GROUP factory in Al-Kharj manufactures cable trays, solar panel structures, and canopies. They also produce custom-made metal parts using CNC machining and hot-dip galvanizing, and can help you calculate weights and quantities before production. For a quick estimate, try their free steel weight calculator.<\/p>\n<p><a href=\"\/en\/contact\/\">Get a Quote<\/a> \u00b7 <a href=\"https:\/\/wa.me\/966575993880\">WhatsApp 0575993880<\/a> \u00b7 <a href=\"\/en\/engineering-calculators\/\">All free engineering calculators<\/a><\/p>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>Equations for calculating the weight of steel with a density of 7850 kg\/m\u00b3: sheets, pipes, sections and reinforcement, with illustrative examples and a table of bar weights.<\/p>","protected":false},"author":1,"featured_media":3225,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center 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\u0648\u0627\u0644\u0645\u0648\u0627\u0633\u064a\u0631 \u0648\u0627\u0644\u062a\u0633\u0644\u064a\u062d: \u0627\u0644\u0645\u0639\u0627\u062f\u0644\u0627\u062a \u0645\u0639 \u0623\u0645\u062b\u0644\u0629","seo_title_en":"Steel Weight Formulas: Sheet, Pipe, Tube and Rebar","seo_description":"\u0637\u0631\u064a\u0642\u0629 \u062d\u0633\u0627\u0628 \u0648\u0632\u0646 \u0627\u0644\u062d\u062f\u064a\u062f \u0628\u0627\u0644\u0645\u0639\u0627\u062f\u0644\u0627\u062a: \u0627\u0644\u0635\u0627\u062c\u060c \u0627\u0644\u0645\u0627\u0633\u0648\u0631\u0629 \u0627\u0644\u062f\u0627\u0626\u0631\u064a\u0629\u060c \u0627\u0644\u0645\u0631\u0628\u0639\u0629 \u0648\u0627\u0644\u0645\u0633\u062a\u0637\u064a\u0644\u0629\u060c \u0648\u0627\u0644\u062a\u0633\u0644\u064a\u062d \u0628\u0645\u0639\u0627\u062f\u0644\u0629 \u0627\u0644\u0642\u0637\u0631\u00b2 \u00f7 162\u060c \u0645\u0639 \u0623\u0645\u062b\u0644\u0629 \u062a\u0648\u0636\u064a\u062d\u064a\u0629 \u0648\u062c\u062f\u0627\u0648\u0644 \u062c\u0627\u0647\u0632\u0629.","seo_description_en":"How to calculate steel weight: sheet plate, round pipe, square and rectangular tube, and rebar with the d\u00b2\/162 rule, with worked examples and ready tables."},"categories":[170],"tags":[325,324,321,322,323],"class_list":["post-3224","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-170","tag-325","tag-324","tag-321","tag-322","tag-323"],"acf":[],"_links":{"self":[{"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/posts\/3224","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/comments?post=3224"}],"version-history":[{"count":0,"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/posts\/3224\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/media\/3225"}],"wp:attachment":[{"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/media?parent=3224"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/categories?post=3224"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mits.sa\/en\/wp-json\/wp\/v2\/tags?post=3224"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}